Get all distinct rows sql
WebJul 25, 2012 · The correct answer is to use a GROUP BY on the columns that you want to have unique answers: SELECT col1, col2 FROM mytable GROUP BY col2 will give you arbitrary unique col2 rows, with their col1 data as well. Share Improve this answer Follow edited Apr 4, 2013 at 16:48 Troy Alford 26.5k 10 63 82 answered Nov 29, 2012 at 2:20 … WebI'm working on a query where I need to count distinct CarId row when the column LocationId is not null and get all CarId if its null or 0 but the query that I tried distincts all the CarId even if its null Desired output: Current Output Im getting a count of 4 but i needed to have 6 as the Coun ... SQL Distinct a column with conditions. Related ...
Get all distinct rows sql
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WebMar 9, 2024 · CREATE TABLE yourtable (column_name varchar2 (13)) ; INSERT ALL INTO yourtable (column_name) VALUES ('1,2,3,string1') INTO yourtable (column_name) VALUES ('3,1,string2') INTO yourtable (column_name) VALUES ('4,5,string3') INTO yourtable (column_name) VALUES ('2,4,string1') SELECT * FROM dual ; Query 1: Web7 Answers Sorted by: 349 This is significantly faster than the EXISTS way: SELECT [EmailAddress], [CustomerName] FROM [Customers] WHERE [EmailAddress] IN (SELECT [EmailAddress] FROM [Customers] GROUP BY [EmailAddress] HAVING COUNT (*) > 1) Share Improve this answer Follow edited Jan 12, 2024 at 1:44 answered Oct 11, 2013 at …
Web3 Answers. If you're not using the id in the result set at all, then the answer above will do the job. If you need at least one Id in the result set for any purpose, then you should alter … WebFeb 2, 2016 · This is the closest I can think of so far. SELECT DISTINCT ID FROM table t1 LEFT OUTER JOIN table t2 ON t1.ID = t2.table.ID WHERE interestingData > 300 …
WebSELECT name, count (*) AS num FROM your_table GROUP BY name ORDER BY count (*) DESC. You are selecting the name and the number of times it appears, but grouping by name so each name is selected only once. Finally, you order by the number of times in DESCending order, to have the most frequently appearing users come first. WebYou can use row_number () to get the row number of the row. It uses the over command - the partition by clause specifies when to restart the numbering and the order by selects what to order the row number on. Even if you added an order by to the end of your query, it would preserve the ordering in the over command when numbering.
WebApr 10, 2024 · Now, all I need to learn is to count all points (from all cols) per row/record and rank them according to their points. Rank each row/record, I mean. Need the sql that does this. mongodb connection refused :WebSep 19, 2024 · Database: Oracle, SQL Server, MySQL, PostgreSQL. This is a commonly recommended method for MySQL and works for all other databases. It involves joining the same table to itself, specifying the matching columns, and deleting all but one duplicate row. Here’s the sample query: mongodb connection with power biWebNov 23, 2016 · select distinct takenBookTitle, user from Books where user = 'username' order by takenBookTitle offset 0 rows fetch next 3 rows only. But with this result I need to retrieve count of all rows (without offset.. fetch). If distinct wasn't necessary It would be done with count (*) OVER (): select takenBookTitle, user, count (*) OVER () AS count ... mongodb configuration optionsWebJul 29, 2011 · Simply use the DISTINCT keyword: SELECT DISTINCT Latitude, Longitude FROM Coordinates; This will return values where the (Latitude, Longitude) combination is unique. This example supposes that you do not need the other columns. mongodb connection string escape charactersWebYes, This code was used to get products by a specified category, but I would like to modify this to get the full list of categories. GetCatgoriesList(). Category is a column in the product table, so there would be duplicate values in the column as it relates to each product. mongodb connection string specify databaseWebFeb 3, 2024 · We'd want to sort data per EMPNO (which is something like your ID ): SQL> select distinct deptno, job from emp order by empno; select distinct deptno, job from emp order by empno * ERROR at line 1: ORA-01791: not a SELECTed expression SQL>. It won't work (as you already know). But, if you use a subquery (or a CTE), then you get this: mongodb connection string for replica setWebApr 8, 2024 · Solution 2: One way in SQL-Server is using a ranking function like ROW_NUMBER: WITH CTE AS ( SELECT c.ContactID, c.Name, m.Text, m.Messagetime, RN = ROW_NUMBER () OVER (PARTITION BY c.ContactID ORDER BY m.MessageTime DESC) FROM dbo.Contacts c INNER JOIN Messages m ON c.ContactID = m.ContactID … mongodb connection string parameters