Find the largest number that divides 1251

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WebJan 13, 2024 · Using Euclid’s division algorithm, find the largest number that divides 1251, 9377 and 15628 leaving remainders 1, 2 and 3 respectively. Solution: The required number when divides 1251, 9377 and 15628 should leave remainder 1, 2 and 3 respectively, 1251 – 1 = 1250, 9377 – 2 = 9375 and 15628 – 3 = 15625 has to be exactly …

Find the largest no that divides 1251, 9377, 15628 leaving …

WebApr 7, 2024 · subtract 1,2,3 from 1251, 9377,15628 respectively. 1251-1=1250, 9377-2=9375, 15628-3=15625. find the hcf of 1250 and 9375. 9375= 1250*7+625. 1250=625*2+0. thus 625 is the hcf. now, find the hcf … WebThe largest number which divides 70 and 125, leaving remainders respectively, is (a) 13 (b) 65 (c) 875 (d) 1750 Solution: (a) Since, 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70-5), 117 = (125 – 8), which is divisible by the required number. home improvement the look

Using Euclid’s division algorithm, find the largest number that …

WebQuestion Using Euclids division algorithm, find the largest number that divides 1251,9377 and 15628 leaving remainders 1,2 and 3, respectively. Medium Solution Verified by … WebJul 5, 2024 · Using Euclid's algorithm find the largest number that divides 1251,9377,15625 leaving remainders 1, 2 and 3 respectively. class 10 real numbers chapter 1 All 64 matches also available in 4K with... WebUsing Euclid’s division algorithm, find the largest number that divides 1251, 9377 and 15628 leaving remainders 1, 2 and 3, respectively. Solution: The remainders of 1251, … himgham cycles

Using Euclid

WebQuestion Find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively. Medium Solution Verified by Toppr Given that on dividing 2053, there is a remainder of 5. This means that 2053−5=2048 is exactly divisible by the required number. Similarly, 967−7=960 is exactly divisible by the required number. WebFundamental Theorem of Arithmetic: Fundamental Theorem of Arithmetic states that every composite number greater than 1 can be expressed or factorised as a unique product of prime numbers except in the order of the prime factors. We can write the prime factorisation of a number in the form of powers of its prime factors. home improvement theme 8 bitWebJun 1, 2024 · Subtract 1, 2, 3 from 1251, 9377, 15628 respectively. 1251 - 1 = 1250, 9377 - 2 = 9375, 15628 - 3 = 15625 Find the HCF of 1250 and 9375 9375 = 1250 x 7 + 625 … home improvement theme song lyrics

"WebOct 10, 2024 · Solution: If the required number divide 1251, 9377 and 15628 leaving remainders 1, 2 and 3 respectively, then this means that number will divide 1250 (1251 − 1), 9375 (9377 − 2) and 15625 (15628 − 3) completely. Now, we just have to find the HCF of 1250, 9375 and 15625. First, let's find HCF of 1250 and 9375 using Euclid's division … " - Find the largest number that divides 1251

Find the largest number that divides 1251

Fundamental Theorem of Arithmetic - NextGurukul

WebMar 21, 2024 · Question. Question asked by Filo student. 15. Find the greatest number which divides 2011 and 2623 leaving remainders 9 and 16. Using Euclid's division algorithm, find the largest number that divides 1251,9377 anve respectively. 15628 leaving remainders 1,2 and 3 respectively. INCERT EXEMPLAR, CBSE201y. Viewed by: … WebMar 22, 2024 · Now, We must find HCF of (3123 & 1250 ) to get HCF of all three numbers. Then, 3125 = 1250 × 2 + 625. 1250 = 625 × 2 + 0. So, HCF of all three numbers is 625. Therefore 625 is the largest number which divides 1251, 9377, 15628 leaving remainders 1, 2 , 3 respectively. _____ Hope my answer is helpful to you.

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WebHence, 625 is the largest number which divides 1251, 9377 and 15628 leaving remainder 1, 2 and 3, respectively. flag. Suggest Corrections. ... Find the largest number that divides 2053 and 967 and leaves a remainder of 5 This means that 20535=2048 is exactly divisible by the required number. WebMar 10, 2024 · Using euclid's division algorithm, find the largest number that divides 1251 , 9377 and 15628 leaving remainders 1,2 and 3 respectively

WebSep 25, 2024 · 1251 -1=1250; 9377-2=9375; 15628-3=15625 Then H.C.F of - 1250=5*5*5*5*2 9375=5*5*5*5*5*3 15625=5*5*5*5*5*5 so, H.C.F (1250,9375,15625)=5*5*5*5=625 Therefore, largest no. that divides 1257,9377,15628 is 625. If it has helped you please mark it as brainliest . Find Math textbook solutions? … WebUse Euclid’s division algorithm to find the HCF of 441, 567, 693. 9. Using Euclid’s division algorithm, find the largest number that divides 1251, 9377 and 15628 leaving remainders 1, 2 and 3, respectively. 10. Prove that 35+ is irrational. 11. Show that 12n cannot end with the digit 0 or 5 for any natural number n. 12.

WebMar 29, 2024 · Transcript. Question 4 The greatest number which when divided by 1251, 9377 and 15628 leaves remainder 1, 2 and 3 respectively is (a) 575 (b) 450 (c) 750 (d) … WebFind the largest number which on dividing 1251,9377 and 12 laves remanent and 3 respectively AN. Solve Study Textbooks Guides. ... Find the largest number which on dividing 1251,9377 and 12 laves remanent and 3 respectively AN. Open in App. Solution. Verified by Toppr. Was this answer helpful? 0. 0. Similar questions. Put the appropriate …

WebApr 27, 2015 · using euclid division algorithm,find the largest number that divide 1251,9377 and 15628 leaving remainder 1,2 and 3 respectively; Prove that n2-n is divisible by 2 for every positive integer n; Find the smallest number that, when divided by 35, 56and 91 leaves reminder of 7 in each case. Ratinalising factor

WebNov 25, 2024 · selected Nov 25, 2024 by sarthaks Best answer Solution: Since, 1, 2 and 3 are the remainders of 1251, 9377 and 15628 respectively. So, 1251 – 1 = 1250 is exactly … home improvement theme song guitarWebMar 10, 2024 · Using euclid's division algorithm, find the largest number that divides 1251 , 9377 and 15628 leaving remainders 1,2 and 3 respectively him gift card where to useWebSolution. It is given that 1, 2 and 3 are the remainders of 1251, 9377 and 15628, respectively. Subtracting these remainders from the respective numbers, we get. 1251 − … himg internal medicine group